2(2y+3)^2-9=23

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Solution for 2(2y+3)^2-9=23 equation: 



2(2y+3)^2-9=23

We move all terms to the left:

2(2y+3)^2-9-(23)=0

We add all the numbers together, and all the variables

2(2y+3)^2-32=0

We move all terms containing y to the left, all other terms to the right

2(2y+3)^2=32

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